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Ask a hyperbolic quotient over a linear in its cosine as the cosine's, before the tangent (#2053)
Rubi's 6.2.5 sech(x)^3/(a + b cosh(x)) and 6.5.3 sech(x)^4/(a + b sech(x))
ran past the corpus's budget. SolveARationalFunctionOfTheHyperbolicTangent
answered each under the tangent of the half argument, a cube of 1 + t^2 beside
a symbolic quadratic, in about 118,000 characters. By Osborn's rule each is a
rational function of a cosine alone over a sum linear in it, which partial
fractions in the cosine answer: 1/(cos(s)^3 (a + b cos(s))) is 2,121
characters. A third mode of SolveAHyperbolicIntegrandAsATrigonometricOne asks
that question beside #2042's, ahead of the tangent, only where s stands in
cos(s) alone and the sums below the bar are linear in it, to the first
power: over the square of one, written out, 6.7.1's
(a + b cosh(x))/(b + a cosh(x))^2 took four times the memory in s. The answer
in s goes back as the rule writes every one, and is checked by its derivative.
Part of #233.
Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
Co-authored-by: Claude Opus 5.5 (1M context) <noreply@anthropic.com>
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