LeetCode Problem #3875 — Construct Uniform Parity Array I Solve LeetCode Construct Uniform Parity Array I using C++ and Binary Search. This solution finds the optimal result using Modified Binary Search in O(n) time.
| Property | Value |
|---|---|
| Problem | Construct Uniform Parity Array I |
| LeetCode | #3875 |
| Difficulty | Easy |
| Language | C++ |
| Algorithm | Modified Binary Search |
| Data Structure | Sorted Array |
| Pattern | Binary Search |
| Time Complexity | O(n) |
| Space Complexity | O(1) |
You are given an array nums1 of n distinct integers.
Exploit sorted ordering or monotonic properties to eliminate half of the search space at each step in
We iterate through the input using Iterative Traversal. By maintaining state efficiently in a Array, we eliminate redundant operations and process each element in optimal time.
- Initialize state variables / data structure (Sorted Array).
- Process elements sequentially using Modified Binary Search.
- Validate boundary conditions and return optimal result.
Consider the standard input for Construct Uniform Parity Array I. Applying Modified Binary Search yields the target result step by step.
- Time Complexity: O(n)
- Space Complexity: O(1)
Binary Search
- Binary Search
- Divide and Conquer
- Search Space
C++
By utilizing Binary Search, each element is processed efficiently, ensuring optimal performance while avoiding unnecessary re-computations.
- Applying standard binary search without accounting for array rotation or duplicates.
- Off-by-one errors when updating boundary pointers (
left = mid + 1vsright = mid - 1). - Integer overflow during midpoint calculation (use
mid = left + (right - left) // 2).
- Tests: Logarithmic search space reduction, boundary handling, and invariant preservation.
- Follow-up: How does performance change if the array contains duplicate elements?