set up parser

Author: RaihanSharif

implement-shell-tools/ls/ls.py

@@ -0,0 +1,23 @@
+import argparse
+import sys
+
+parser = argparse.ArgumentParser(
+    prog="a simple version of ls",
+    description="ls command line tool which can accept 0 or more arguements" \
+    "and take -a and -1 flags")
+
+parser.add_argument("-a", action="store_true", help="show all files, including dot files")
+
+# can't store as an attribute of Namespace object, because 1 is not a valid python identifier
+# but can store under the name given in the dest argument. When working with this
+# parser, look for "opt_one", not "1".
+parser.add_argument("-1", dest="opt_one", action="store_true", help="show one file/directory name per line")
+
+# takes 0 more arguments, if none are given, sets "." as default value
+parser.add_argument("paths", nargs="*", help="file/directory path(s) to display", default=".")
+
+args = parser.parse_args()
+
+print(args)
+
+# def getDirectoryEntries(path, aFlag=args.a):