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"""
Prefill / Decode 计算过程校验脚本
用微型模型模拟文章中的完整推理流程,验证:
1. Prefill 一次性计算所有 token 的 K/V,存入 Cache
2. Decode 每步只算新 token 的 Q/K/V,从 Cache 读取历史 K/V
3. 有 Cache 和重算全序列的 Attention 输出完全一致(数值验证)
4. 每一步的矩阵形状与文章标注一致
5. 两阶段的 FLOPs 对比
用法:
python prefill_decode_validate.py # 默认运行
python prefill_decode_validate.py --verbose # 打印每步形状
"""
import torch
import torch.nn.functional as F
import math
import argparse
# ── 微型模型参数(与文章成比例缩小,几秒内跑完)──
D_MODEL = 64 # 隐藏维度(文章:4096)
NUM_HEADS = 4 # 注意力头数(文章:32)
HEAD_DIM = D_MODEL // NUM_HEADS # 每头维度 = 16(文章:128)
NUM_LAYERS = 2 # Decoder 层数(文章:32)
VOCAB_SIZE = 100 # 词表大小
PROMPT_LEN = 4 # prompt token 数
DECODE_STEPS = 3 # 生成 token 数
# 固定随机种子,保证可复现
torch.manual_seed(42)
parser = argparse.ArgumentParser()
parser.add_argument("--verbose", "-v", action="store_true", help="打印每步矩阵形状")
args = parser.parse_args()
def shape(t):
"""返回 tensor 的形状字符串"""
return str(list(t.shape))
def log(msg):
if args.verbose:
print(msg)
print(f"{'='*60}")
print(f"模型配置:d_model={D_MODEL}, heads={NUM_HEADS}, head_dim={HEAD_DIM}")
print(f" layers={NUM_LAYERS}, prompt_len={PROMPT_LEN}, decode_steps={DECODE_STEPS}")
print(f"{'='*60}\n")
# ══════════════════════════════════════════════════════════
# 一、构建微型模型:Embedding + 每层的 W_Q/W_K/W_V/W_O + FFN + LM Head
# ══════════════════════════════════════════════════════════
embedding = torch.randn(VOCAB_SIZE, D_MODEL) # token embedding 表
lm_head = torch.randn(D_MODEL, VOCAB_SIZE) # 输出投影到词表
# 每层一套权重(用 dict of tensors 模拟,2 层足够验证)
layers = []
for l in range(NUM_LAYERS):
layers.append({
"W_Q": torch.randn(D_MODEL, D_MODEL),
"W_K": torch.randn(D_MODEL, D_MODEL),
"W_V": torch.randn(D_MODEL, D_MODEL),
"W_O": torch.randn(D_MODEL, D_MODEL),
"W_1": torch.randn(D_MODEL, D_MODEL * 2), # FFN up (SwiGLU 双倍)
"W_2": torch.randn(D_MODEL * 2, D_MODEL), # FFN down
})
# 模拟 prompt token ids
prompt_ids = torch.randint(0, VOCAB_SIZE, (PROMPT_LEN,)) # (4,)
# ══════════════════════════════════════════════════════════
# 二、Prefill:一次性处理全部 prompt token
# ══════════════════════════════════════════════════════════
print("── 二、Prefill 阶段 ──")
print(f"输入 token ids: {prompt_ids.tolist()}")
# 2.1 Embedding lookup
X = embedding[prompt_ids] # (4, 64)
log(f"2.1 Embedding 后 X: {shape(X)}")
# 存储每层的 KV Cache
kv_cache = []
# 逐层前向
for l_idx, layer in enumerate(layers):
# 2.2 Q/K/V 投影
Q = X @ layer["W_Q"] # (4, 64) × (64, 64) = (4, 64)
K = X @ layer["W_K"] # (4, 64) × (64, 64) = (4, 64)
V = X @ layer["W_V"] # (4, 64) × (64, 64) = (4, 64)
log(f"2.2 Layer {l_idx} Q/K/V: {shape(Q)}, {shape(K)}, {shape(V)}")
# 2.3 拆分为多头
# (4, 64) → (4, 4, 16) → (4, 4, 16) 即 (num_heads, seq_len, head_dim)
Q = Q.view(PROMPT_LEN, NUM_HEADS, HEAD_DIM).transpose(0, 1) # (4, 4, 16)
K = K.view(PROMPT_LEN, NUM_HEADS, HEAD_DIM).transpose(0, 1)
V = V.view(PROMPT_LEN, NUM_HEADS, HEAD_DIM).transpose(0, 1)
log(f"2.3 多头拆分后 Q/K/V: {shape(Q)}, {shape(K)}, {shape(V)}")
# 2.4 注意力计算(带因果掩码,这里因为是 Decoder)
scale = math.sqrt(HEAD_DIM)
attn_scores = (Q @ K.transpose(-2, -1)) / scale # (4, 4, 4) × (4, 16, 4) = (4, 4, 4)
log(f"2.4 注意力得分 S: {shape(attn_scores)}")
# 因果掩码
causal_mask = torch.triu(torch.ones(PROMPT_LEN, PROMPT_LEN), diagonal=1).bool()
attn_scores = attn_scores.masked_fill(causal_mask, float('-inf'))
attn_weights = F.softmax(attn_scores, dim=-1) # (4, 4, 4)
O = attn_weights @ V # (4, 4, 4) × (4, 4, 16) = (4, 4, 16)
log(f"2.4 Attention 输出 O_h: {shape(O)}")
# 2.5 多头拼接 + 输出投影
O = O.transpose(0, 1).contiguous().view(PROMPT_LEN, D_MODEL) # (4, 64)
O = O @ layer["W_O"] # (4, 64)
log(f"2.5 输出投影后: {shape(O)}")
# 残差连接
X = X + O
# FFN (简化为单层,因为校验重点在 Attention)
ffn_out = X @ layer["W_1"] # (4, 128)
# 简化为 GELU(不做 SwiGLU 门控以保持代码简洁)
ffn_out = F.gelu(ffn_out)
ffn_out = ffn_out @ layer["W_2"] # (4, 64)
X = X + ffn_out # 残差连接
log(f"2.5 FFN + 残差后: {shape(X)}")
# 2.6 存入 KV Cache(形状与 2.3 一致:(num_heads, seq_len, head_dim))
kv_cache.append({"K": K.clone(), "V": V.clone()})
print(f" Layer {l_idx}: K_cache={shape(K)}, V_cache={shape(V)}")
# Prefill 最后一步:取最后一个位置 → LM Head → 第一个 token
last_hidden = X[-1:] # (1, 64)
log(f"2.6 最后一层输出取末尾位置: {shape(last_hidden)}")
logits = last_hidden @ lm_head # (1, 100)
first_token_id = torch.argmax(logits, dim=-1).item()
print(f" 第一个输出 token: {first_token_id}\n")
# ══════════════════════════════════════════════════════════
# 三、Decode:逐 token 生成(用 KV Cache)
# ══════════════════════════════════════════════════════════
print("── 三、Decode 阶段 ──")
current_token_id = first_token_id
generated_tokens_with_cache = [current_token_id]
for step in range(DECODE_STEPS):
print(f"\n Step {step+1} (当前 token: {current_token_id}):")
# 3.1 只取当前 token 的 embedding
x_new = embedding[current_token_id].unsqueeze(0) # (1, 64)
log(f" 3.1 x_new: {shape(x_new)}")
# 逐层前向
for l_idx, layer in enumerate(layers):
# Q/K/V 投影(注意:GEMV!)
Q_new = x_new @ layer["W_Q"] # (1, 64)
K_new = x_new @ layer["W_K"] # (1, 64)
V_new = x_new @ layer["W_V"] # (1, 64)
log(f" 3.1 Q_new/K_new/V_new: {shape(Q_new)}")
# 拆分为多头
Q_new = Q_new.view(1, NUM_HEADS, HEAD_DIM).transpose(0, 1) # (4, 1, 16)
K_new = K_new.view(1, NUM_HEADS, HEAD_DIM).transpose(0, 1)
V_new = V_new.view(1, NUM_HEADS, HEAD_DIM).transpose(0, 1)
# 3.2 追加到 KV Cache
K_full = torch.cat([kv_cache[l_idx]["K"], K_new], dim=1) # (4, 5+step, 16)
V_full = torch.cat([kv_cache[l_idx]["V"], V_new], dim=1)
kv_cache[l_idx]["K"] = K_full
kv_cache[l_idx]["V"] = V_full
log(f" 3.2 K_cache 追加后: {shape(K_full)}")
# 3.3 注意力计算(只用新 token 的 Q,但 K/V 用全量缓存)
scale = math.sqrt(HEAD_DIM)
attn_scores = (Q_new @ K_full.transpose(-2, -1)) / scale # (4, 1, seq_len)
log(f" 3.3 S: {shape(attn_scores)}")
attn_weights = F.softmax(attn_scores, dim=-1)
O_new = attn_weights @ V_full # (4, 1, 16)
# 多头拼接
O_new = O_new.transpose(0, 1).contiguous().view(1, D_MODEL) # (1, 64)
O_new = O_new @ layer["W_O"]
x_new = x_new + O_new # 残差
# FFN
ffn_out = x_new @ layer["W_1"]
ffn_out = F.gelu(ffn_out)
ffn_out = ffn_out @ layer["W_2"]
x_new = x_new + ffn_out
# LM Head → 下一个 token
logits = x_new @ lm_head # (1, 100)
current_token_id = torch.argmax(logits, dim=-1).item()
generated_tokens_with_cache.append(current_token_id)
print(f" 输出 token: {current_token_id}")
print(f"\n 生成序列(有 KV Cache): {generated_tokens_with_cache}")
# ══════════════════════════════════════════════════════════
# 四、正确性验证:逐 token 重算全序列 Attention(无 Cache)
# ══════════════════════════════════════════════════════════
print(f"\n{'='*60}")
print("四、正确性验证:重算全序列 Attention(无 Cache)vs KV Cache")
print(f"{'='*60}")
# 重新从 Prefill 开始(不依赖之前的 kv_cache)
torch.manual_seed(42) # 重置随机种子... 但权重没变,所以直接重用
# 重建 embedding 和 layer(使用相同的权重,这里直接重用上面的)
# Re-run prefill 拿到第一个 token(结果应相同)
X2 = embedding[prompt_ids]
for l_idx, layer in enumerate(layers):
Q = X2 @ layer["W_Q"]
K = X2 @ layer["W_K"]
V = X2 @ layer["W_V"]
Q = Q.view(PROMPT_LEN, NUM_HEADS, HEAD_DIM).transpose(0, 1)
K = K.view(PROMPT_LEN, NUM_HEADS, HEAD_DIM).transpose(0, 1)
V = V.view(PROMPT_LEN, NUM_HEADS, HEAD_DIM).transpose(0, 1)
scale = math.sqrt(HEAD_DIM)
attn_scores = (Q @ K.transpose(-2, -1)) / scale
causal_mask = torch.triu(torch.ones(PROMPT_LEN, PROMPT_LEN), diagonal=1).bool()
attn_scores = attn_scores.masked_fill(causal_mask, float('-inf'))
attn_weights = F.softmax(attn_scores, dim=-1)
O = attn_weights @ V
O = O.transpose(0, 1).contiguous().view(PROMPT_LEN, D_MODEL)
O = O @ layer["W_O"]
X2 = X2 + O
ffn_out = X2 @ layer["W_1"]
ffn_out = F.gelu(ffn_out)
ffn_out = ffn_out @ layer["W_2"]
X2 = X2 + ffn_out
last_hidden2 = X2[-1:]
first_token_id2 = torch.argmax(last_hidden2 @ lm_head, dim=-1).item()
assert first_token_id == first_token_id2, "Prefill 结果不一致"
# Decode 阶段:每一步都重算全部 Attention(费时,但理论上等价)
seq_token_ids = prompt_ids.tolist() + [first_token_id2]
generated_tokens_no_cache = [first_token_id2]
for step in range(DECODE_STEPS):
current_id = generated_tokens_no_cache[-1]
seq_token_ids.append(current_id)
seq_tensor = torch.tensor(seq_token_ids)
# 整个序列重算
X_all = embedding[seq_tensor] # (N, 64),N = 5 + step
for l_idx, layer in enumerate(layers):
Q = X_all @ layer["W_Q"]
K = X_all @ layer["W_K"]
V = X_all @ layer["W_V"]
Q = Q.view(len(seq_token_ids), NUM_HEADS, HEAD_DIM).transpose(0, 1)
K = K.view(len(seq_token_ids), NUM_HEADS, HEAD_DIM).transpose(0, 1)
V = V.view(len(seq_token_ids), NUM_HEADS, HEAD_DIM).transpose(0, 1)
scale = math.sqrt(HEAD_DIM)
seq_len = len(seq_token_ids)
attn_scores = (Q @ K.transpose(-2, -1)) / scale
causal_mask = torch.triu(torch.ones(seq_len, seq_len), diagonal=1).bool()
attn_scores = attn_scores.masked_fill(causal_mask, float('-inf'))
attn_weights = F.softmax(attn_scores, dim=-1)
O = attn_weights @ V
O = O.transpose(0, 1).contiguous().view(seq_len, D_MODEL)
O = O @ layer["W_O"]
X_all = X_all + O
ffn_out = X_all @ layer["W_1"]
ffn_out = F.gelu(ffn_out)
ffn_out = ffn_out @ layer["W_2"]
X_all = X_all + ffn_out
# 取最后一个位置
next_token = torch.argmax(X_all[-1:] @ lm_head, dim=-1).item()
# 验证:重算的结果应与 KV Cache 的结果完全一致
assert next_token == generated_tokens_with_cache[step + 1], \
f"Step {step}: 无 Cache={next_token}, 有 Cache={generated_tokens_with_cache[step + 1]} — 不一致!"
generated_tokens_no_cache.append(next_token)
print(" ✓ 有 KV Cache 与无 Cache(全量重算)生成的 token 序列完全一致")
print(f" 序列: {generated_tokens_no_cache}")
# ══════════════════════════════════════════════════════════
# 五、FLOPs 对比
# ══════════════════════════════════════════════════════════
print(f"\n{'='*60}")
print("五、FLOPs 对比(1 层 Attention 的 Q/K/V 投影)")
print(f"{'='*60}")
def gemm_flops(m, k, n):
"""矩阵乘法 A(m,k) × B(k,n) 的 FLOPs 估算"""
return 2 * m * k * n
# Prefill: (4, 64) × (64, 64) → 三个投影
prefill_proj_flops = 3 * gemm_flops(PROMPT_LEN, D_MODEL, D_MODEL)
prefill_data_bytes = D_MODEL * D_MODEL * 2 # 读 W_Q(FP16)
prefill_ai = prefill_proj_flops / prefill_data_bytes
# Decode: (1, 64) × (64, 64) → 三个投影
decode_proj_flops = 3 * gemm_flops(1, D_MODEL, D_MODEL)
decode_data_bytes = D_MODEL * D_MODEL * 2
decode_ai = decode_proj_flops / decode_data_bytes
print(f" Prefill 1 token Q/K/V 投影: {gemm_flops(1, D_MODEL, D_MODEL):,} FLOPs")
print(f" Prefill 4 token Q/K/V 投影: {prefill_proj_flops:,} FLOPs")
print(f" 数据搬运(读 W_Q): {prefill_data_bytes:,} bytes")
print(f" 算术强度: {prefill_ai:.2f} FLOPs/byte")
print(f"")
print(f" Decode 1 token Q/K/V 投影: {decode_proj_flops:,} FLOPs")
print(f" 数据搬运(读 W_Q): {decode_data_bytes:,} bytes")
print(f" 算术强度: {decode_ai:.2f} FLOPs/byte")
print(f"")
print(f" 结论: Decode 的算术强度仅为 Prefill(4 tokens) 的 {decode_ai/prefill_ai:.0%}")
# 文章中的对比(按文章参数):
article_prefill_flops = 134_000_000
article_prefill_data = 32_000_000
article_decode_flops = 33_500_000
article_decode_data = 32_000_000
article_prefill_ai = article_prefill_flops / article_prefill_data
article_decode_ai = article_decode_flops / article_decode_data
print(f"\n 文章中的参考值:")
print(f" Prefill 算术强度: ~{article_prefill_ai:.1f} FLOPs/byte")
print(f" Decode 算术强度: ~{article_decode_ai:.2f} FLOPs/byte")
print(f" Decode/Preill: {article_decode_ai/article_prefill_ai:.0%}")
print(f"\n{'='*60}")
print("验证通过:KV Cache 在数学上与全量重算完全等价,但 Decode 每步比")
print("Prefill 计算量小得多——同时数据搬运量几乎不变,导致 memory-bound。")
print(f"{'='*60}")