Extract file using pattern

[rmalenko]

Hello,

Prompt me the correct pattern, please.

I have archives named like this:

test_mysql_20230427-025501
test_mysql_20230426-034501
test_mysql_20230425-015101

and I would like to get file test_mysql_20230427-025501
using
borg extract --dry-run --list ssh://b@b.com/./test.staging.com::test_mysql_20230427-.*

but the archive doesn't find using this pattern

[ThomasWaldmann]

You can't extract multiple archives at once / in one borg invocation (if that was your intention).

But you can do a little shell scripting, like (untested):

export BORG_REPO=...
for ARCH in `borg list --short` ; do
    borg extract ::$ARCH
done

[ThomasWaldmann]

Closing this as outdated: it has seen no activity for a long time and predates the current borg releases.

If this still affects you on a current version - borg 1.4.x (stable) or the borg 2.0.0 beta - please open a new discussion with up-to-date details.